X=5(3x^2-5)

Solution for X=5(3x^2-5) equation:

X=5(3X^2-5)

We move all terms to the left:

X-(5(3X^2-5))=0


We calculate terms in parentheses: -(5(3X^2-5)), so:

5(3X^2-5)

We multiply parentheses

15X^2-25

Back to the equation:

-(15X^2-25)


We get rid of parentheses

-15X^2+X+25=0

a = -15; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·(-15)·25
Δ = 1501
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1501}}{2*-15}=\frac{-1-\sqrt{1501}}{-30}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1501}}{2*-15}=\frac{-1+\sqrt{1501}}{-30}
$